A long distance runner started a course running at an average speed of 6 mph. One and one-half hours later, a cyclist traveled the same course at an average speed of 12 mph.
The answer is 3 hours but how come?
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Show me another »How long after the runner started did the cyclist overtake the runner?
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set the distances traveled = to each other
d = st
6(1.5) +6t = 12t
t is time after 1.5 hours
9 = 6t
t = 1.5
total time is 1.5+1.5 = 3.0 hours
d = st
6(1.5) +6t = 12t
t is time after 1.5 hours
9 = 6t
t = 1.5
total time is 1.5+1.5 = 3.0 hours
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